What angle θ3 does the ray refracted into the water make with the normal to the surface? use 1.33 for the index of refraction of water. g?
Accepted Solution
A:
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Answer: θ₃ = 27.574°
Explanation: To answer this question, we will use Snell's law twice. Part 1: getting θ₂: We have: n1 is n of air = 1 n2 is n of glass = 1.58 θ₁ is the incident angle = 38° θ₂ is the angle of refraction we want to find. Apply Snell's law to get θ₂ as follows: n1 sin(θ₁) = n2 sin(θ₂) 1 * sin(38) = 1.58 sin(θ₂) sin (θ₂) = 0.3896 θ₂ = 22.933°
Part 2: getting θ₃: We have: n2 is n of glass = 1.58 n3 is n of water = 1.33 θ₂ is the incident angle = 22.933° θ3 is the angle of refraction we want to find. Apply Snell's law to get θ₂ as follows: n2 sin(θ₂) = n3 sin(θ₃) 1.58 * sin(22.933) = 1.33 sin(θ₃) sin (θ₃) = 0.462897 θ₂ = 27.574°