MATH SOLVE

5 months ago

Q:
# 20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by the function f(d) = 1.11√d. Part a: determine f(2) and explain what it represents. Part B: The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}. What does this tell you about the basin. Part C: how long would it take a rock to drop from the rim to the bottom of the basin?

Accepted Solution

A:

Answer:Part a) [tex]f(2)=1.57\ sec[/tex]It takes 1.57 seconds for an object to fall a distance of 2 feet Part b) see the explanationPart c) [tex]2,165.43\ sec[/tex]Step-by-step explanation:Letf(d) -----> the time in seconds it takes for an object to fall d -----> distance in feet we have[tex]f(d)=1.11\sqrt{d}[/tex]Part a): Determine f(2) and explain what it representswe know thatf(2) represent the time in seconds it takes for an object to fall a distance of 2 feetFor [tex]d=2\ ft[/tex]substitute in the function above and solve for f(2)[tex]f(2)=1.11\sqrt{2}[/tex][tex]f(2)=1.57\ sec[/tex]thereforeIt takes 1.57 seconds for an object to fall a distance of 2 feet Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}What does this tell you about the basin?The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft soThe maximum height of the basin is 3,805,774 ftPart c) How long would it take a rock to drop from the rim to the bottom of the basin?we know thatThe distance from the rim to the bottom of the basin is equal to the maximum height of the basinso [tex]d=3,805,774\ ft[/tex]substitute the value of d in the function f(d)[tex]f(d)=1.11\sqrt{3,805,774}[/tex][tex]f(d)=2,165.43\ sec[/tex]