Apasses through A(-3,0) and B(-6,5). What is the equation of the line that passes through the origin and is parallel to AB?OA. 5x - 3y = 0B. -* + 3y = 0c. 5x - 3y = 0D. 3x + 5y = 0E. -3x + 5y = 0

Answer:B. 5x + 3y = 0Step-by-step explanation:Parallel lines have the same slope.The slope-intercept form of an equation of a line:[tex]y=mx+b[/tex]m - slopeb - y-interceptThe formula of a slope:[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]We have the points A(-3, 0) and B(-6, 5). Substitute:[tex]m=\dfrac{5-0}{-6-(-3)}=\dfrac{5}{-3}=-\dfrac{5}{3}[/tex]The line passes through the origin, therefore the y-intercept is equal to 0.Therefore we have the equation:[tex]y=-\dfrac{5}{3}x[/tex]Convert to the standard form [tex]Ax+By=C[/tex][tex]y=-\dfrac{5}{3}x[/tex]         multiply both sides by 3[tex]3y=-5x[/tex]                add 5x to both sides[tex]5x+3y=0[/tex]